Question

CLASS 9TH SCIENCE CH8 MOTION​

Answer 1

☞Given :-

A train starting from a Railway Station and moving with uniform acceleration attains a speed of 40 km h in 10 minutes.

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☞To find :-

Find the acceleration of train.

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☞Formula used :-

$v = \frac{given \: km \times 1000}{60 \times 60}$

$a = \frac{v - u}{t}$

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☞Solution :-

$u = {0m \: s}^{ - 1}$

$v = {40 km \: h}^{ - 1}$

Now,

Convert 40 km in sec .

$v = \frac{40 \times 1000}{60 \times 60} = {11.11m \: s}^{ - 1}$

T = 10 min = 10 * 60 = 600s

A = ?

Than,

$a = \frac{v - u}{t}$

$a = \frac{11.11 - 0}{600}$

$a = 0.0185 {m \: s}^{ - 1}$

Hence,

The acceleration of the train is 0.0185 m/s -1.

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Hopes, it's helpful.

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