Question

class in a class of 50 students 1 by 5 of the total play football 3 by 5 play click and the remaining play basketball

a basketball =10 b football =10 c cricket =30​

Answer 1

Answer:

Let A and B represents the students play cricket and football respectively.

Let x be the percentage of students play neither cricket nor football.

Given:-

n(A∩B)=10

n(A)=50

n(B)=40

Now,

n(A)+n(B)+x−n(A∩B)=100

⇒50+40+x−10=100

⇒x=110−90=20

Hence 20% students play neither cricket not foot ball

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Answer 2

$= \frac{3}{5} - \frac{1}{5} \\ \\ = \frac{2}{5}$

$Football \\ \\ = \frac{1}{5} \times 50 \\ \\ = 10$

$Cricket \\ \\ = \frac{3}{5} \times 50 \\ \\ = 30$

$Basketball \\ \\ = \frac{2}{5} \times 50 \\ \\ = 20$