Question

Class mark and class size of the class interval are 25 and 10 respectively then the class interval is ?​

Answer 1

Lower limit = l

Upper limit = u

Class size = u - l

=> 10 = u - l

=> 10 + l = u

Class mark = ( u + l )/2

=> 25 = ( u + l )/2

=> 25*2 = u + l

Putting value of u,

=> 50 = 10 + l + l

=> 50 - 10 = 2*l

=> 40/2 = l

=> l = 20

So, u = l + 10 = 30

Class interval : 20 - 30

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Alternative method:

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x = class size /2 = 10/2 = 5

Lower limit = class mark - x = 25 - 5 = 20

Upper limit = class mark + x = 25 + 5 = 30

So, class interval : 20 - 30

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Answer 2

Answer:

Ans :20-30

Step-by-step explanation:

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