Question

class mark and class size of the class interval are 25 and 10 respectively then the class interval is?
please give me step by step explanation.​

Answer 1

Answer:

HOPE U HELP THIS

Step-by-step explanation:

Let Lower Limit be L

∴ Upper Limit =L+10 [ Since, Class Width =10]

Now, we know that

ClassMark=(LowerLimit+UpperLimit)÷2

∴ (L+L+10)÷2=25 [Class Mark 25 given]

⇒ 2L+10=50

⇒ 2L=40

⇒ L=20

∴ Lower Limit of the class =20

Upper Limit of the class =20+10=30

The required class is 20−30