Question

class now ninth cbse board​

Answer 1

The hand writing is not understoodable so, sorry

Answer 2

Answer:

Step-by-step explanation:

Given angle ∠ACD is 110°

Angle of a straight line is 180°

⇒ ∠ACB + ∠ACD = 180°

   ∠ACB = 180° - 110°

              = 70°

By exterior angle theorem,

  ∠CAB + ∠ABC = 110°

*Either  ∠CAB or ∠ABC should be given in question substitute that angle in last equation you will get answer and to check angle sum property add all 3 interior angles ans will be 180°