class now ninth cbse board
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The hand writing is not understoodable so, sorry
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Step-by-step explanation:
Given angle ∠ACD is 110°
Angle of a straight line is 180°
⇒ ∠ACB + ∠ACD = 180°
∠ACB = 180° - 110°
= 70°
By exterior angle theorem,
∠CAB + ∠ABC = 110°
*Either ∠CAB or ∠ABC should be given in question substitute that angle in last equation you will get answer and to check angle sum property add all 3 interior angles ans will be 180°
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