Question

CLASS REVISION PROGRAMME
MATHEMATICS - CBSE
kill based questions :(Statistics)
Following distribution gives the marks obtained, out of 150, by the students of Class 19 mwen tass
test.
Marks 0-25 25 - 50 50 – 75 | 75 – 100 100 – 125 125 – 150|150 – 175 | 175 – 200|
Number of 10 15 22 30 I 28 | 27 | 12 | 6
students
Find the mean and mode of the data.​

Answer 1

Mean = 102.5 & Mode  = 95  for given Data

Step-by-step explanation:

Marks      Frequency    cf         Mean Marks    (mean - 112.5)/25  

0-25               10             10             12.5             -4                -40

25-50             15            25             37.5             -3                -45

50-75              22           47             62.5            -2                 -44

75-100            30            77             87.5            -1                  -30

100-125          28            105             112.5            0                0

125-150           27            132             137.5          1                  27

150-175           12            144             162.5           2                 24

175-200           6             150             187.5           3                18

                   150                                                                     -60

Mean = 112.5  + 25 * (-60)/150

          = 112.5 - 10

          = 102.5

Mean = 102.5

Mode lies in 75 - 100

Mode  = 75  +  25 * (30 - 22)/(( 30 - 22) + (30 - 28))

= 75 + 25 * 8 /10

= 75 + 20

= 95

Lear More

Given the mean of the following data is 53, find the value of x and y.

https://brainly.in/question/10374934

Based on the grouped data below find the median

https://brainly.in/question/1138306

Answer 2

Mean=97.5

Mode=95

Step-by-step explanation:

Class mark$(x_i)=\frac{lower\;limit+upper\;limit}{2}$

By using direct method

$Mean(\bar x)=\frac{\sum f_ix_i}{\sum f_i}$

$\sum f_i=150$

$\sum f_ix_i=14625$

Mean$(\bar x)=\frac{14625}{150}$=97.5

Mean=97.5

Mode=$l+\frac{f_1-f_0}{2f_1-f_0-f_2}\times h$

Where l=Lower limit of modal class

$f_1$=Frequency of modal class

$f_0$=Frequency of class preceding modal class

$f_2$=Frequency of class succeeding modal class

h=Size of class

Modal class 75-100

l=75

$f_1=30$

$f_0=22$

$f_2=28$

h=25

Substitute the values in the formula

Mode=$75+\frac{30-22}{2(30)-22-28}\times 25$

Mode=75+20=95

Mode=95

#Learns more:

https://brainly.in/question/683000:answered by Jaya