Question

class Vll

Mathematics
practical geometry
exercise 10.4
Question no. 2
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Answer 1

Answer:

hiii friend

Explanation:

Construct ∆PQR if PQ = 5 cm, m ∠PQR = 105° and m∠QRP = 40°.

(Hint: Recall angle-sum property of a triangle)

Solution:

Given: m∠PQR = 40°, m∠QRP = 105°

∵ m∠PQR + m∠QRP + ∠QPR = 180° (Angle sum property of a triangle)

105° + 40° + ∠QPR = 180°

145° + ∠QPR = 180°

∴ ∠QPR = 180° – 145° = 35°

Steps of construction:

(i) Draw PQ = 5 cm.

(ii) Draw ∠QPR = 35° and ∠PQR = 40° to meet each other at R.

(iii) ∆PQR is the required triangle.

[Using AAS or ASA criterion]