Question

class width of two consecutive class interval 5-10 and 11-16 is​

Answer 1

Answer:

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In order to make class intervals even we need to add 0.5 and reduce 0.5 from class boundaries

1−5 = 0.5−5.5

6−10 = 5.5−10.5

11−15 = 10.5−15.5

so , lower boundary of class 11−15 = 10.5