Question

Class Work
Tuesday
4th August
Lesson
Motion
Exercise: (Calculating Acceleration)
1. While traveling along a highway, a, driver shows
from 24m/s to 15 m/s in 12 seconds. What is the
automobiles acceleration? (Remember that a negative
value indicates a slowing down on deceleration)​

Answer 1

This is a very easy question, but for you.....

Let's find the solution of it!

So,

Here,

$u = 24 \: m/s$

$v = 15 \: m/s$

$t = 12 \: s$

Where

$u = initial \: velocity$

$v = final \: velocity$

and

$t = time$

Now,

$(a = acceleration)$

$a = \frac{v - u}{t}$

$a = \frac{15 - 24}{12}$

$a = \frac{ - 9}{12}$

Therefore,

$a = - 0.75 \: {ms}^{ - 2}$

Answer 2

Explanation:

Initial Velocity of the car=24m/s

Final Velocity of the car= 15m/s

Time Taken= 12 seconds

We know

$a = \frac{v - u}{t}$

Therefore,

$a = \frac{15m/s - 24m/s}{12s}$

$a = \frac{ - 9m/s}{12s}$

$a = \frac{ - 3}{4}ms^{ - 2}$

$a = -0.75 {ms}^{ - 2}$

Therefore it will have a negative retardation of -0.75 metre per second square.