Math, asked by Ishu307, 1 year ago

CLASS X

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Answers

Answered by Aishwarya00001
3

Please find the answer in the attachment.

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Answered by smarty2020
0

Step-by-step explanation:

secθ+tanθ=p ......... (1)

∵sec²θ − tan²θ = 1

or (secθ+tanθ) (secθ−tanθ) = 1

or secθ − tanθ = 1/p ....... (2)

Adding (1) & (2) we get

2secθ = p+1/p

or secθ = (p²+1)/2p

∴ cosθ = 1/secθ = 2p/(p²+1)

∴ sinθ= √(1−cos²θ)

= √[1−{2p/(p²+1)}²

= √1−4p²/(p² +1)²

= √p⁴ +2p²+1−4p²/(p² +1)²

= √(p⁴−2p²+1)/(p²+1)

= √(p²−1)²/p² +1

=(p²−1)/(p²+1)

∴cosecθ=1/sinθ=1[(p²−1)(p²+1)]

cosecθ =(p²+1)/(p²−1)

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