Question

class X chapter 1 similarity maths 2​

Answer 1

Given that,

PQ = 6, QR = 8, PR = 10, LM = 3, MN = 4, LN = 5

Now,

$\frac{PQ}{LM} = \frac{6}{3} = 2$

and,

$\frac{QR}{MN} = \frac{8}{4} = 2$

and,

$\frac{PR}{LN} = \frac{10}{5} = 2$

Since,

PQ/LM = QR/MN = PR/LN = 2

∴ ∆PQR ∼ ∆LMN by SSS similarity.

Hope It Helps :)

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