Question

Class X Math
Test for Real Numbers
Max Marks : 35
Max Time : 45 mins
1. The LCM and HCF of two numbers are 240 and 12 respectively. If one of the numbers is 60, then find the other number. 3 marks
2. Without actually performing the long-division, state will have a terminating or non-terminating repeating decimal expansion. 3 marks
3. Write whether the rational number will have a terminating decimal expansion or a non-terminating repeating decimal expansion. 3 marks
4. The HCF and LCM of two numbers are 9 and 360 respectively. If one number is 45, write the other number. 3 marks
5. What is the HCF of 52 and 130? 3 marks
6. Express as a rational number in the simplest form. 4 marks
7. Prove that is an irrational number. 4 marks
8. Show that is an irrational number. 4 marks
9. Show that one and only one of n, n + 2 and n + 4 is divisible by 3. 4 marks
10. Using Euclid’s division algorithm, find the HCF of 56, 96 and 404. 4 marks

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Answer 1

Answer:

Are you fan of R.Ashwin ???

Answer 2

Color prejudice in India

There is no lawful color prejudice in India. Indian constitution guarantees equal rights to every citizen, irrespective of their color, religion or any other demographic distinction. Having said this, it is essential to note that the society is not free from prejudices. Preference of color and caste is still prevalent in the society. Laws have been made to protect the rights of every individual but the reluctance of the people to follow these laws instead of the pre-conceived societal notions has created an anomaly.

The law of the land doesn’t permit such discriminations and it is the fault of the societal mindset that the regional and color prejudice is still present in India.The decimal expansion of the rational number 432453 will terminate after how many places of decimals? (2013)

Solution:

Important Questions for Class 10 Maths Chapter 1 Real Numbers 1

Question 2.

Write the decimal form of 129275775

Solution:

Non-terminating non-repeating.

Question 3.

Find the largest number that will divide 398, 436 and 542 leaving remainders 7, 11, and 15 respectively.

Solution:

Algorithm

398 – 7 = 391, 436 – 11 = 425, 542 – 15 = 527

HCF of 391, 425, 527 = 17

Question 4.

Express 98 as a product of its primes.

Solution:

2 × 72