Question

Class X Maths Chapter 4 Ex . 4.3
Ques 2 :- Find the roots of the quadratic equations given in Ques1 by applying Quadratic Formula
iii) 4x² + 4√3x + 3 = 0.


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Answer 1

Step-by-step explanation:

Let's solve your equation step-by-step.

$→4x2+4√3x+3=0$

$→4x2+6.928203x+3=0$

For this equation: a=4

$b=6.928203230275509,c=3$

$→4x2+6.928203x+3=0$

Step 1: Use quadratic formulae with

a=4, b=6.928203230275509, c=3.

$→x=−b±√b2−4ac^2a$

x=−(6.928203)±√(6.928203)2−4(4)(3)2(4)

$x=√−6.928203230275509±$

$−√7.10542737601002e−158$

Answer:

No real solutions.

$\color{red}{Hope/ it /helps}$

Answer 2

Let's solve your equation step-by-step.

→4x2+4√3x+3=0→4x2+4√3x+3=0

→4x2+6.928203x+3=0→4x2+6.928203x+3=0

For this equation: a=4

b=6.928203230275509,c=3b=6.928203230275509,c=3

→4x2+6.928203x+3=0→4x2+6.928203x+3=0

Step 1: Use quadratic formulae with

a=4, b=6.928203230275509, c=3.

→x=−b±√b2−4ac^2a→x=−b±√b2−4ac2a

x=−(6.928203)±√(6.928203)2−4(4)(3)2(4)

x=√−6.928203230275509±x=√−6.928203230275509±

−√7.10542737601002e−158−√7.10542737601002e−158

Answer:

No real solutions.

Good Molning ♡