Question

CLASS X

Two resisters with resistances 5 ohm and 10 ohm are to be connected to a battery of 6V . calculate the strenght of the total current in the circuit when resistors are connected

1. in parallel

2. in series

3. which set up will provide us with minimum current

ANSWER IT AS SOON AS POSSIBLE...PLZ

Answer 1

1.In parallel
R1=5 ohm
R2=10 ohm
V=6V
Effective resistance=1/5+1/10=1/R
=3/10=R
Effective resistance=10/3 ohms
I=V/R
I=6×3/10=1.8A
The current flowing through the circuit is 1.8A.

2.In series
Effective resistance=R1+R2=15 ohms
I=V/R=6/15=3/5A
The current flowing through the circuit is 3/15A.

3.Resistance is inversely proportional to current.
Resistance will be more in series.So, Current usage will be minimum when we connect them in series.