Math, asked by NidhraNair, 1 year ago

Class XI
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Math
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Complex numbers
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Answered by Anonymous
7

LHS

=(√5- 2i)(√5+ 2i)-9

=(√5)²-(2i)²-9

=5-4i²-9 (i²= - 1)

=5+4-9

=0

=RHS

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Answered by asingh90262
7

Step-by-step explanation:

hope it helps you...................

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