Question

class8
maths
chapter - 1
verify
a×(b+c) = (a×b) + (a×c)
for a=$\frac{1}{2}b=\frac{3}{5} c=\frac{-2}{7}$

Answer 1

$\huge{\boxed{\sf{SOLUTION :}}}$

L.H.S

a × (b + c)

$\frac{1}{2} \times ( \frac{3}{5} + \frac{( - 2)}{7} )$

$\frac{1}{2} \times ( \frac{ 21-10}{35} )$

$\frac{ 11}{70}$

R.H.S

(a × b) + (a × c)

$( \frac{1}{2} \times \frac{3}{5} ) + ( \frac{1}{2} \times \frac{( - 2)}{7} )$

$\frac{3}{10} + \frac{( - 2)}{14}$

$\frac{3}{10} + ( \frac{ - 1}{7})$

L.C.M of 10 and 7 is 70

$\frac{21 - 10}{70}$

$\frac{11}{70}$

Hence,

L.H.S = R.H.S

It is proved