Math, asked by cpsycho267, 9 months ago

Class9 lesson2 polynomials​

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Answered by shreyampatil24
3

Answer:

HOPE THIS MAY HELP YOU

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Answered by SGAkshayGRA
3

Answer:

(x-5)(x+1)

Step-by-step explanation:

Ans) p(x) = x3 - 3x2 - 9x - 5 Factors of 5 = 1,5,-1,-5 p(1) = 13 - 3 x (1)2 - 9 x (1) - 5 = 1 -3 - 9 - 5 = 1 - 17 = - 16 ≠ 0 p(-1) = (-1)3 x 3 x (-1)2 - 9 x (-1) -5 = -1 - 3 + 9 - 5 = -9 + 9 = 0 p(-1) =0 ∴ (x+1) is a factor of p(x) p(x) ÷ (x+1) x3 - 3x2 - 9x - 5 ÷ x + 1 = x2 - 4x - 5 x2 - 4x - 5 x2 - 5x + 1x - 5 = x ( x - 5) + 1 ( x - 5) = ( x - 5) ( x + 1)

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