classify the decimal form of the given rational no. into terminating and non terminating recurring type :100/3
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Answers
Step-by-step explanation:
We have,
A) 513=51×2013
So, the denominator 5 of 513 is of the form 2m×5n, where m,n are non-negative integers.
Hence, 513 has terminating decimal expansion.
B) 112
So, the denominator 11 of 112 is not of the form 2m×5n, where m,n are non-negative integers.
Hence, 112 has non-terminating decimal expansion.
C) 1629=24×5029
So, the denominator 16 of 1629 is of the form 2m×5n, where m,n are non-negative integers.
Hence, 1629 has terminating decimal expansion.
D) 12517=5
Answer:
answer is
Step-by-step explanation:
We have,
A) 513=51×2013
So, the denominator 5 of 513 is of the form 2m×5n, where m,n are non-negative integers.
Hence, 513 has terminating decimal expansion.
B) 112
So, the denominator 11 of 112 is not of the form 2m×5n, where m,n are non-negative integers.
Hence, 112 has non-terminating decimal expansion.
C) 1629=24×5029
So, the denominator 16 of 1629 is of the form 2m×5n, where m,n are non-negative integers.
Hence, 1629 has terminating decimal expansion.
D) 12517=5