classify The expression6x²+10x-35as ____
Answers
Answer:
Selina solutions
Grade 6
Mathematics
CONCISE Mathematics - Middle School - 6
Framing Algebraic Expressions (Including Evaluation)
Exercise 21
Question 19
Framing Algebraic Expressions (Including Evaluation) | Exercise 21
Question 19
CHAPTERS
1. Number System (Consolidating the Sense of Numberness)
2. Estimation
3. Numbers in India and International System (With Comparison)
4. Place Value
5. Natural Numbers and Whole Numbers (Including Patterns)
6. Negative Numbers and Integers
7. Number Line
8. HCF and LCM
9. Playing with Numbers
10. Sets
11. Ratio
12. Proportion (Including Word Problems)
13. Unitary Method
14. Fractions
15. Decimal Fractions
16. Percent (Percentage)
17. Idea of Speed, Distance and Time
18. Fundamental Concepts (Algebra)
19. Fundamental Operations (Related to Algebraic Expressions)
20. Substitution (Including Use of Brackets as Grouping Symbols)
21. Framing Algebraic Expressions (Including Evaluation)
22. Simple (Linear) Equations (Including Word Problems)
23. Fundamental Concepts (Geometry)
24. Angles (With their Types)
25. Properties of Angles and Lines (Including Parallel Lines)
26. Triangles (Including Types, Properties and Construction)
27. Quadrilateral
28. Polygons
29. The Circle
30. Revision Exercise on Symmetry (Including Constructions on Symmetry)
31. Recognition of Solids
32. Perimeter and Area of Plane Figures
33. Data Handling (Including Pictograph and Bar Graph)
34. Mean and Median
EXERCISES
1. Exercise 21
Q19) If a = -10, evaluate :
(i) 3a – 2
(ii)\ a^2+8a(ii) a
2
+8a
(iii)\ \frac{1}{5}\times a^2(iii)
5
1
×a
2
Solution
Transcript
Solution:
(i) 3a – 2
= (3 x a) - 2
= 3 x (-10) - 2= - 30 - 2 = -32
(ii)\ a^2+8a(ii) a
2
+8a
= (a x a) + (8 x a)
= (-10 x (-10)) + (8 x (-10))
= 100 + (-80)
= 100 - 80
= 20
(iii)\ \frac{1}{5}\times a^2(iii)
5
1
×a
2
=\frac{1}{5}\times(-10)\times(-10)=
5
1
×(−10)×(−10)
=\frac{1}{5}\times100=
5
1
×100
= 20
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