Classify the quadrilateral formed by the vertices A(1, 1) B(3, 3) C(7, 1) and D(5, –1)
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Answer:
AB=√(1-3)^2+(1-3)^2
=√(-2)^2+(-2)^2
=√4+4
=√8
BC=√(3-7)^2+(3-1)^2
=√(-4)^2+(2)^2
=√16+4
=√20
2√5
CD=√(7-5)^2+(1+1)^2
=√(2)^2+(2)^2
=√4+4
=√8
AD=√(1-5)^2+(1+1)^2
=√(-4)^2+(2)^2
=√16+4
=√20
=2√5
Now,as AB=CD n BC=AD
therefore,ABCD is a llgm
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