Question

classmate Date Pace 2) A vehicle is running at speed of 45 km / hr. If it is stopped in seconds by applying brakes, calculate the retardation of vehicle and distance travelled before its stopping.​

Answer 1

Answer:

Corrected Question-

A vehicle is running at speed of 45 km / hr. If it is stopped in 3 seconds by applying brakes, calculate the retardation of vehicle and distance travelled before its stopping.​

Explanation:

Initial speed u= 45 km/h = 12.5 m/s

Final Speed v= 0 m/s

$v=u+at$

$0= 12.5+a(3)$

$-12.5=3a$

so, $a=-4.167ms^{-2}$

Retardation is 4.17$ms^{-2}$

For displacement, $v^{2} -u^{2} =2as$

Solving for s, $s= 18.75 m(approx)$