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Construct a triangle PQR in which
OR=6cm Q= 60° and PR- PQ=2cm.((class*9))
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Answer:
Step-by-step explanation:
Steps of construction:-
1)Draw a ray QX and cut off a line segment QR =6cm from it.
2))Construct a ray QY making an angle of 60 degree with QR and produce YQ To form a line YQY.
3)Cut off a line segment QS=2cm from QY.
4)Join RS
5(Draw perpendicular bisectors of Rs intersecting QY at a point P.
6)Join PR ..
Then, PQR is the required ∆.
Hope helped!!!
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