Question

classmate
Date
Page
Revision Questions.
A gun of mass 3 kg fires a
bullet of mass 15 g the bullet takes
0 .005 sec to move through a barrel
ob gun and aquires velocity of 125 m per s
calculate:Velocity with which gun recoil
? thee force exerted on gun man ​

Answer 1

Answer:

velocity of gun recoil= 0.53 m/s

force exerted on man=75kg/s2

explanation: or, 125×15=3000 × X ( velocity of gun recoil, taken as X )

or, 125×15÷3000=x

or, 0.53 m/s

$125 \times 1000 \div 5 \\ = 25000m \\ = \: \frac{25000}{1000} \\ = 25km \\ now \\ force = m \times a \\ \: \: \: \: \: \: \: \: = 25 \times 3 \\ = 75km \: per \: s \: square$