Question

classmate
Page
calculate the enthalpy of formation of methane
from following data
C(g)+ O2(g)
» CO2g ; deltaH =-393.5kj
H2(g) + 1/2O2 gives
Н2 0 : Дн°equal -285.9kj
CH4 (g) + 202 - CO2 + H2O ; DH = -890kJ​

Answer 1

Answer:

-74.80

Explanation:

∆Hf° of methane is -74.80kj/mol-1

and ∆Hc° ( enthalpy of combustion ) is -890kj/mol-1