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then the
If zis one of the zeroes of the
Polynomial x² + 3x² - 4x-12
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zeroes of the polynomial are
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Step-by-step explanation:
You have
(x−2)(x2+ax−k)=x3−3x2+4x+2k
Multiplying out:
x3+ax2−kx−2x2−2ax+2k=
x3+(a−2)x2−(k+2a)x+2k=x3−3x2+4x+2k
So, equating terms, 2a+k=−4 , 2−a=3 , and thus a=−1 , k−2=−4 , k=−2
k=−2 .
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