Math, asked by bhagyasee, 9 months ago

clear explanation how does the total surface area of a box change if each dimension is doubled and each dimension is tripled

Answers

Answered by rudraaggarwal239982
5

Answer:

Step-by-step explanation:

let length =L

width=B

height=H

surface area of box=2{LB+BH+HL}

(a) all dimensions are double

so ,

new length =2L

width=2B

height =2H

now surface area=2{(2L)(2B)+(2B)(2H)+(2H)(2L)}

=4 x 2{LB+BH+HL}

compare we see 4times surface of box

(b) if all dimensions triples

then

surface area of box=2{(3L)(3B)+(3B)(3H)+(3H)(3L)}

=9 x 2 {LB+BH+HL}

we see surface area of box now, 9 times

yes " i find if dimensions raised n times

surface area of box then n^2 times

by above observation .

hope u understand...

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