Question

Clear se
Q6) Prove that 3+V5 is an
irrational​

Answer 1

Answer:

let us assume that 3+√5 is rational number

Now,

3+√5=(a÷b)

(here a and b are co-prime numbers)

√5=[(a÷b)-3]

Here {(a-3b)÷b} is a rational number

But we know that√5 is irrational number

So {(a-3b)÷b} is also irrational number

so our assumption is wrong.

3+√5 is irrational number

Hence proved

Step-by-step explanation:

so problem solved