Math, asked by wwwkamaljitnirmalsin, 8 months ago

Click on photo above
Find value :-

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Answered by brainlyaryan12

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➡️ $\large{x^{a-b} × x^{b-c} × x^{c-a}}$

=> $\large{x^{a-b+b-c+c-a}}$

=> $\large{x^0}$

$\large\orange{\fbox{\pink{\therefore\: Value\:is\:1}}}$

$\huge{\purple{\bigstar{\blue{\text{Hope it helps...}}}}}$

Answered by Prem7600

x^a-b * x^b-c * x^c-a

=x^a-b+b-c+c-a

=x^(a-a)(b-b)(c-c)

=x^0

So the answer for this question is 1 because anything raise to the power of 0 is one.

Hope this helps you.

Please mark this as Brainliest.

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