Question

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Answer 1

Answer:

options B ......

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Answer 2

$as \: two \: resistors \: are \: in \: parrallel$

$so$

$\frac{1}{1} + \frac{1}{1} = \frac{1}{r}$

$\frac{2}{1} = \frac{1}{r}$

$r = \frac{1}{2} Ω = 0.5Ω$

$two \: resistors \: are \: in \: series$

$so \:$

$2Ω + 3Ω = 5Ω$

$total \: resistance \: = 5Ω + 0.5Ω \\ = > 5.5Ω$

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