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this question is from mentors package.
Take common:
3^4(1+1+1) / 2^4(1+1) × 4^4(1+1+1+1) / 6^4(1+1+1+1+1+1)
3^4.3 / 2^4.2 × 4^4.4 / 6^4.6
3^5 / 2^5 × 4^5 / 6^5
now take power 5 common
( 3/2 × 4/6 )^5
(2/2)^5= 1
hence, LHS = 1
So, RHS = 2018^0= 1
so the answer is 0
Take common:
3^4(1+1+1) / 2^4(1+1) × 4^4(1+1+1+1) / 6^4(1+1+1+1+1+1)
3^4.3 / 2^4.2 × 4^4.4 / 6^4.6
3^5 / 2^5 × 4^5 / 6^5
now take power 5 common
( 3/2 × 4/6 )^5
(2/2)^5= 1
hence, LHS = 1
So, RHS = 2018^0= 1
so the answer is 0
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