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Hey user Here is ur answer⤵⤵⤵
radius of small circle (r) = 35/2
radius of big circle (R) = 42/2
So, now area of required area = area of big circle - area of small circle
Area of circle = πr^2
Therefore area of big circle = π (42/2)^2
and area of small circle = π (35/2)^2
Area of required area = π (R^2 - r^2)
◆ π is taken as common
= π [(42/2)^2 - 35/2)^2]
= π (42/2 +35/2) ( 42/2- 35/2)
it's bcoz of identity i.e.
(a^2-b^2) = (a+b) (a-b)
= π (77/2) (7/2)
= 22/7 × 77/2 × 7/2
= 11 × 77/2
= 847/2
= 423.5 cm^2
Hope so it helps u..
#Be Brainly
#Be Frndly
radius of small circle (r) = 35/2
radius of big circle (R) = 42/2
So, now area of required area = area of big circle - area of small circle
Area of circle = πr^2
Therefore area of big circle = π (42/2)^2
and area of small circle = π (35/2)^2
Area of required area = π (R^2 - r^2)
◆ π is taken as common
= π [(42/2)^2 - 35/2)^2]
= π (42/2 +35/2) ( 42/2- 35/2)
it's bcoz of identity i.e.
(a^2-b^2) = (a+b) (a-b)
= π (77/2) (7/2)
= 22/7 × 77/2 × 7/2
= 11 × 77/2
= 847/2
= 423.5 cm^2
Hope so it helps u..
#Be Brainly
#Be Frndly
abhishekrajput76:
thanks
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