Math, asked by ignatiaphumilekhoane, 11 months ago

Clive has 2 pairs of yellow socks, 3 pairs of red socks, 4 pairs of black socks and 6 pairs of white socks in his drawer. There is a power failure due to load shedding while he is getting dressed and he cannot see which colour socks he is putting on. What is the probability that
he will put on:
4.2.1 red socks?
4.2.2 yellow socks?
4.2.3 black or white socks ?

Answers

Answered by amitnrw
0

Answer:

Step-by-step explanation:

2 pair of yellow socks = 4 yellow socks

3 pairs of red socks = 6 red socks

4 pair of Black socks = 8 black socks

6 pair of white socks = 12 white socks

total socks = 30 socks

4.2.1  - Red socks

Probability of 1st red sock = 6/30 = 1/5

Probability of second red sock = 5/29

Probability of both red socks = (1/5)(5/29)  = 1/29

4.2.2  - Yellow socks

Probability of 1st Yellow sock = 4/30 = 2/15

Probability of second Yellow sock = 3/29

Probability of both yellow socks = (2/15)(3/29)  = 2/145

4.2.3 black or white socks

Black socks = (8/30)(7/29) = 56/870

White Socks = (12/30)(11/29) = 132/870

black or white socks  = 56/870 + 132/870

= 188/870

= 31/145

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