Question

closed circular loop of radius 10 cm is placed in a region which contains a non-uniform but constant magnetic field directed into the plane of the loop. The emf induced in the loop is
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Answer 1

Given:

A closed circular loop of radius 10 cm is placed in a region which contains a non-uniform but constant magnetic field directed into the plane of the loop.

To find:

EMF induced ?

Calculation:

As per Faraday's Law of Electromagnetic Induction, we can say:

$\sf \: EMF = \dfrac{d \phi}{dt}$

• Here $\phi$ is magnetic flux.

$\sf \implies\: EMF = \dfrac{d(B \times area)}{dt}$

$\sf \implies\: EMF = \dfrac{d(B \times \pi {r}^{2} )}{dt}$

$\sf \implies\: EMF = \pi {r }^{2} \times \dfrac{d(B)}{dt}$

• Now, B is constant, so dB/dt will be zero.

$\sf \implies\: EMF = \pi {r }^{2} \times 0$

$\sf \implies\: EMF = 0 \: volt$

So, induced EMF is zero volt.

Answer 2

Given:-

A closed circular loop of radius 10 cm is placed in a region which contains a non-uniform but constant magnetic field directed into the plane of the loop.

To Find:-

EMF induced ?

Calculation:

As per Faraday's Law of Electromagnetic Induction, we can say:

EMF=dΦ/dt.

• Here ϕ is magnetic flux.

EMF=d(B×area)/dt

EMF=d(B×πr²)/dt

EMF= πr²×d(B)/dt

• Now, B is constant, so dB/dt will be zero.

EMF= πr²×0

EMF= 0 volt

So, induced EMF is zero volt.

☆Hope it helps you☆