Computer Science, asked by KumarAditya17, 9 months ago

Closed. This question needs details or clarity. It is not currently accepting answers. Add details and clarify the problem you’re solving. This will help others answer the question. You can edit the question or post a new one. Closed 6 mins ago. (Private feedback for you) Edit question when i chhoose 1 img then then data in console is Content-Disposition: form-data; name="0"; filename="paris.jpg" and if io choose 2 images then data is :- Content-Disposition: form-data; name="0"; filename="paris.jpg" Content-Disposition: form-data; name="1"; filename="france.jpg" and if 3 files:- Content-Disposition: form-data; name="0"; filename="paris.jpg" Content-Disposition: form-data; name="1"; filename="france.jpg" Content-Disposition: form-data; name="2"; filename="india.jpg" and so on... that means input type file name is increasing how can i move all the files i choose how to fetch file names with increasing images choosed $filename = $_FILES['0'] $filename = $_FILES['1'] and so on..

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0

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Answered by Anonymous
2

Answer:

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