Question

Clsss 10th exercise 5.2 question number 17

Answer 1

To find = 20th term from the last term of given AP

a=3

d =5

if we write reverse this AP

253,248,243.................................8,3

a =253

d= -5

n=20

$= a + 19d$

$= 253 + 19 \times - 5$

$= 253 - 95$

$t20 =158$

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