Question

cm.
2)
In the adjoining figure, centre of two circles is O. Chord AB of bigger circle intersects the smaller
circle in points P and Q. Show that AP BQ
Q
A А
B В
M
Prove that:- AP = BQ
Construction: Draw seg OM I chord AB, A-M-B
Proof:-
1) In the bigger circle, seg OM 1
chord AB
2): AM = BM
3) In the smaller circle, seg OM
[Construction]
1 chord PO
[Perpendicular drawn from the centre of the circle to the chord
4) PM =
bisects the chord]
5) AM-PM =
[Subtracting (4) form (2)]
6). AP = BQ
[A-P-Mand B-Q-M]​

Answer 1

Answer:

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