Math, asked by aaditya1978, 7 months ago

cm and
the diameters of two balls be
cm, find the diameter of the third
2
A measuring jar of internal diameter 10 cm is partially filled with water. Four equal spherical
balls of diameter 2 cm each are dropped in it and they sink down in water completely. What
will be the change in the level of water in the jar ?
I need solutions fast ​

Answers

Answered by Anonymous
3

Question :

A measuring jar of internal diameter 10 cm is partially filled with water. Four equal sphericalballs of diameter 2 cm each are dropped in it and they sink down in water completely. Whatwill be the change in the level of water in the jar ?

Answer :

Using Capital letters for Cylindrical Jug;

D = 10cm ; R = 5cm

and let the level of water is at H height

r = 2cm

Since 4 similar spherical balls are dropped

so,

Volume of 4 spherical balls =

4 \times  \frac{4}{3} \pi {r}^{3}

 = 4 \times  \frac{4}{3}  \times  {5}^{3}

 =  \frac{16}{3}  \times 125\pi

 = \frac{2000}{3} \pi  \:  \: {cm}^{3}

So, the increase in the volume of jug =

 =  \frac{2000}{3} \pi

Let the increase in level be "h" cm

Now,

increase in volume = {\pi{R}^2h}

 \frac{2000}{3} \pi = \pi {R}^{2} h

Cancel π from both sides

\frac{2000}{3}={5}^{2}×h

\frac{2000}{3×25}=h

 h=\frac{80}{3}cm

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