Question

cm
Density of water
Weight of water displaced by body
1gcm
= Volume x Density xg
Apparent loss in weight (W-W.) in water
Hence,
Weight of the water displaced
by solid body
Apparent loss in weight (W - W) in kerosene
Weight of kerosene
displaced by solid
Volume of water collected in measuring cylinder
Similarly, the weight of the kerosene displaced by the solid. We notice,​

Answer 1

Answer:

Weight of object in vacuum = W ; It's density = ρ

Therefore, the volume of the object will be V = W/ρ

Now, this object is immersed in a fluid of density ρ1

Its apparent loss in weight would be equal to the weight of fluid displaced (as is evident from Archimedes' principle)

Apparent loss = ρ1V = ρ1W/ρ

Therefore, the weight in water = weight in vacuum - the loss in weight

Weight in water = W−ρ1W/ρ

= W(1−ρ1/ρ)