cn any1 ans dis picture?
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the answer is n/2 pls mark me as best for first entering the ans
urs pixie
urs pixie
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The answer is (2) 1.
At least 1 number should be greater than 0 to make the average 0.
For example:
Take the n numbers as: '-1', '-1', '-1', '-1' .......(n-1) times and '(n-1)'
Here there are (n-1) negative terms and one positive term.
Average = [(-1)+(-1)+...(n-1) times + (n-1)]/n
= [-(n-1) + (n-1)]/n = 0
At least 1 number should be greater than 0 to make the average 0.
For example:
Take the n numbers as: '-1', '-1', '-1', '-1' .......(n-1) times and '(n-1)'
Here there are (n-1) negative terms and one positive term.
Average = [(-1)+(-1)+...(n-1) times + (n-1)]/n
= [-(n-1) + (n-1)]/n = 0
tigerslover:
thnx
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