Cn anyone help me with this...will mark as brainlest.... how 2 factorise them (sum and product )
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Answered by
1
⭐⭐Hello friend...Ur answer is here⤵⤵
⚫ x^2+14x+48
➡x^2+8x+6x+48
➡x(x+8)+6 (x+8)
➡(x+8)(x+6)
⚫y^2+2y-3
➡y^2-3y+y-3
➡y (y-3)+1 (y-3)
➡(y-3)(y+1)
⚫x^2-11x-42
➡x^-14x+3x-42
➡x (x-14)+3 (x-14)
➡(x-14)(x+3)
⚫x^2+12x-45
➡x^2+15x-3x-45
➡x (x+15)-3 (x+15)
➡(x+15)(x-3)
⚫4y^2-4y+1
➡4y^2-2y-2y+1
➡2y (2y-1)-1 (2y-1)
➡(2y-1)(2y-1) Or (2y-1)^2
I hope it is helpful to you☺
⚫ x^2+14x+48
➡x^2+8x+6x+48
➡x(x+8)+6 (x+8)
➡(x+8)(x+6)
⚫y^2+2y-3
➡y^2-3y+y-3
➡y (y-3)+1 (y-3)
➡(y-3)(y+1)
⚫x^2-11x-42
➡x^-14x+3x-42
➡x (x-14)+3 (x-14)
➡(x-14)(x+3)
⚫x^2+12x-45
➡x^2+15x-3x-45
➡x (x+15)-3 (x+15)
➡(x+15)(x-3)
⚫4y^2-4y+1
➡4y^2-2y-2y+1
➡2y (2y-1)-1 (2y-1)
➡(2y-1)(2y-1) Or (2y-1)^2
I hope it is helpful to you☺
Anonymous:
what??
Answered by
1
HEYA...
HERE IS YOUR ANSWER....
1] x^2 + 14x + 48
= x^2 + 8x + 6x + 48
= x[x+8] + 6[x+8]
= [x+6] [x+8]
2] y^2 + 2y - 3
= y^2 -y + 3y - 3
= y[y-1] + 3[y-1]
= [y-1] [y+3]
3] x^2 - 11x- 42
= x^2 + 3x - 14x - 42
= x[x+3] -14[x+3]
= [x+3] [x- 14]
4] x^2 + 12x - 45
= x^2 +15x -3x - 45
= x[x+15] -3[x+15]
= [x+15] [x-3]
5] 4y^2 - 4y +1
= 4y^2 - 2y -2y + 1
= 2y [2y - 1] - 1 [2y - 1]
= [2y-1] [2y-1]
HOPE HELPED...
AND ALSO MRK BRAINLIEST IF HELPED...
HERE IS YOUR ANSWER....
1] x^2 + 14x + 48
= x^2 + 8x + 6x + 48
= x[x+8] + 6[x+8]
= [x+6] [x+8]
2] y^2 + 2y - 3
= y^2 -y + 3y - 3
= y[y-1] + 3[y-1]
= [y-1] [y+3]
3] x^2 - 11x- 42
= x^2 + 3x - 14x - 42
= x[x+3] -14[x+3]
= [x+3] [x- 14]
4] x^2 + 12x - 45
= x^2 +15x -3x - 45
= x[x+15] -3[x+15]
= [x+15] [x-3]
5] 4y^2 - 4y +1
= 4y^2 - 2y -2y + 1
= 2y [2y - 1] - 1 [2y - 1]
= [2y-1] [2y-1]
HOPE HELPED...
AND ALSO MRK BRAINLIEST IF HELPED...
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