CBSE BOARD X, asked by NRay, 1 year ago

cn anyone plzz explain the method of completing the square....... for the given equation
Proper steps one will be marked Brainliest......
#class10

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Answers

Answered by gaurav2013c
5
5x^2 - 6x - 2 = 0

Step 1.) Transfer the constant term in RHS

=> 5x^2 - 6x = 2

Step 2.) Divide the whole equation by the coficient of x square .

=> x^2 - 6x/5 = 2/5

Step 3.) Add the square of half of the coficient of x in both sides.

=> x^2 - 6x/5 + (3/5)^2 = 2/5 + (3/5)^2

=> ( x - 3/5)^2 = 2/5 + 9 /25

=> ( x - 3/5)^2 = (10+9) / 25

=> (x- 3/5)^2 = 19/25

=> x - 3/5 = sqrt ( 19 / 25)

=> x = 3/5 plus minus sqrt (19) / 5


x = (3 + sqrt 19) /5

And

x = (3 - sqrt 19) / 5

NRay: Thnx a ton:)
Answered by adityaceo2001Aditya
1
Plzz mark it as brainliest
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adityaceo2001Aditya: Thanx bro for the brainliest
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