Question

co efficient of linear expansion of 2 metals A and B are 13 ×10^-6 and 19×10^-6. calculate the length of metal A which expands as much as 2.6cm of metal B for same raise in temperature
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Answer 1

Answer:

3.8 cm

Explanation:

A:    ( L2-L1 ) / L1 ( t2-t1 ) = 19*10^-6

       L2-L1 = ( 13*10^-6 )( L1 )( t2-t1)

B:     ( L2-L1 ) / 2.6 ( t2-t1 ) = 13*10^-6

        L2-L1 = (19*10^-6)( 2.6 )( t2-t1)

given,

          L2-L1 of A = L2-L1 of B

          ( 13*10^-6 )( L1 )( t2-t1) = (19*10^-6)( 2.6 )( t2-t1)

          we can cancel t2-t1 as they are the same (given in question)

            ( 13*10^-6 )( L1 ) = (19*10^-6)( 2.6 )

             L1 = (19*10^-6)( 2.6 ) / ( 13*10^-6 )

                  = 3.8 cm