Question

Co-ordinate of point P on a number line is -7 then find the co-ordinate of point on the number line which are at a distance of 8 unit from point P

Answer 1

Answer:

1 & -15

Step-by-step explanation:

number line is x-axis

Point P on number line -7 is actually (-7, 0)

to find coordinates which are at a distance of 8 units on number line itself.

only x co-ordinate will change and y will remain same.

let's a new point would be (x,0)

distance between (x,0) & (-7,0) = 8

Distance= √(x-(-7))² + (0-0)²

= 8 =√(x+7)²

squaring both sides

=(x+7)² = 64

taking square root both sides

= x+7 = +8

=x+7 =8 or x+7 = -8

= x = 1 or x = 15

show coordinates of point of number line which are at a distance of 8 units from point P are 1 & -15

Answer 2

Answer:

355th is currently not allowed