co secant theta minus cos theta whole square is equals to 1 minus cos theta by 1 + cos theta
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If you're asking an NCERT book question, I remember the question as:
Prove (cosecx - cotx)^2 = 1 - cosx/ 1 + cosx)
Solution: (1/sinx - cosx/sinx) ^2
= ( 1 - cosx/sinx)^2
= (1 - cosx)^2/ sin^2x
= (1 - cosx)^2/ 1 - cos^2x
= (1 - cosx)^2/ (1 - cosx) ( 1 + cosx)
= 1 - cosx/ 1 + cosx
Hence, proved.
Prove (cosecx - cotx)^2 = 1 - cosx/ 1 + cosx)
Solution: (1/sinx - cosx/sinx) ^2
= ( 1 - cosx/sinx)^2
= (1 - cosx)^2/ sin^2x
= (1 - cosx)^2/ 1 - cos^2x
= (1 - cosx)^2/ (1 - cosx) ( 1 + cosx)
= 1 - cosx/ 1 + cosx
Hence, proved.
saijahnavi:
i didnot understand any thing
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I hope this will help you
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