Question

Ⲫⳙⲉ⳽ⲧⲓⲟⲛ:)
Coᥒ⳽tɾᥙᥴt ᥲ tɾɩᥲᥒɠꙆᥱ ABC ɩᥒ ωᖾɩᥴᖾ BC=8ᥴຕ,∠B=45° ᥲᥒᑯ AB−AC =3.5ᥴຕ​

Answer 1

$\huge\mathfrak\pink{Answer}$

1.Draw base BC of length 8cm

2.Now, let's draw ∠B=45 ∘

.Let the ray be BX

3.Open the compass to length AB−AC=3.5cm.

Since AB−AC=3.5cm is positive.

So, BD will be above line BC

From point B as center, cut an arc on ray BX.

Let the arc intersect BX at D

4.Join CD

5.Now, we will draw perpendicular bisector of CD

6.Mark point A where perpendicular bisector intersects BD

7.Join AC

Result:∴△ABC is the required triangle.

Answer 2

Answer:

hope u undestand it.. thanks for deleting my previous ans..