Coca Cola and Wine (UNSOLVED]
rcentage
whisky replaced is :
(d)
(Hotel Management 1991)
he ratio 7:2. How much
Te containing milk and
(Railways 1992)
(d) 91 ml
ad girls in such a way
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Coca Cola and Wine
(d) 65
s partly by bus at
tance covered by
Ple
= MCQ
DESCRIPTION
640 km
- either 10 paise
is :
60
e but he mixes
water in the
A tumbler consists of mixture of Coca Cola and wine
consisting 18% Coca Cola.
8 litres of the mixture is drawn out of the tumbler which is
again replaced by wine. If the present percentage of Coca Cola
is 15%, then what would be the quantity of the mixture in the
tumbler?
much water
25% ?
C
of milk
further
Answers
he Coca Cola Christmas Analogue Train Set
Resplendent in a Coke® Red livery, this officially licensed train set for the adult collector offers an almost timeless iconic interpretation of the Coca-Cola® brand, representing the logistics involved in bringing Coke®, by rail, from the factory to the doorstep.
The set is an ideal starter layout and offers the model railway enthusiast a brilliant and unique train set with an engine & wagons featuring the distinctive Coca-Cola® design. It includes a good starter layout that can also be enjoyed by those new to the hobby and easily extended later.
What better way to wake up on Christmas morning than to see a Christmas Train Set running around the Christmas tree. With this set you can create a whole new set of magical memories for the whole family to enjoy for years to come.
What’s in the box?
Rolling Stock
0-4-0 Diesel Shunter Locomotive, Coca Cola®
Closed Box Van, Coca Cola®
Container Wagon, Coca Cola®
Track & Accessories
1st Radius Starter Oval
Train Controller (R8250)
Wall Plug Transformer (P9000W)
Re-Railer
Hope this helpsssssssss.
Mark as brainliest.
1. There was 48 litres of mixture in the tumbler initially.
2. The man added 150 ml of water.
3. There is no solution to this problem.
Problem 1:
A tumbler consists of a mixture of Coca Cola and wine, which is 18% Coca Cola. 8 litres of the mixture are drawn out and replaced with wine, after which the mixture has 15% Coca Cola. How much mixture was in the tumbler initially?
Let's call the initial amount of mixture in the tumbler "x". We know that 18% of x is Coca Cola, which means 82% of x must be wine. We can set up the equation:
0.18x = amount of Coca Cola in the mixture initially
0.82x = amount of wine in the mixture initially
When 8 litres of the mixture are drawn out, the amount of Coca Cola that is removed is:
0.18x * (8/x) = 1.44
Similarly, the amount of wine that is added back to the tumbler is also 8 litres. At this point, we have 0.15x Coca Cola and 0.85x wine in the tumbler. We can set up another equation:
0.15x = amount of Coca Cola in the mixture after replacement
0.85x = amount of wine in the mixture after replacement
We can use these equations to solve for x:
0.18x - 1.44 = 0.15x
0.03x = 1.44
x = 48
Problem 2:
A man has 60 ml of whisky, and he replaces some of it with water so that the new mixture is 7 parts whisky to 2 parts water. How much water did he add?
Let's call the amount of water that the man added "x". Then the new mixture is:
7 parts whisky : 2 parts water = 7/9 : 2/9
We can set up the equation:
(7/9) * (60 ml) = amount of whisky in the new mixture
(2/9) * (60 ml + x) = amount of water in the new mixture
We can solve for x:
(7/9) * (60 ml) = (2/9) * (60 ml + x)
420 = 120 + 2x
300 = 2x
x = 150
Problem 3:
A milk container has 2 litres of milk that is 20% water. How much milk should be taken out and replaced with pure milk so that the new mixture is 25% water?
Let's call the amount of milk that should be taken out "x". Then the amount of milk that remains in the container after x is removed is 2 - x. When x amount of milk is removed, the amount of water in the container is 0.2x, and the amount of milk is 2 - 0.2x.
When x amount of pure milk is added back to the container, the amount of milk becomes 2 - 0.2x + x = 2 + 0.8x, and the amount of water becomes 0.2x. We want the new mixture to be 25% water, so we can set up the equation:
0.25(2 + 0.8x) = 0.2x
We can solve for x:
0.5 + 0.2x = 0.2x
0.5 = 0
This is a contradiction, so there is no solution to this problem
for such more question on percentage
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