Chemistry, asked by kaushalrocks758, 9 months ago

[CoCl2(NH3)4]+ IUPAC name

Answers

Answered by TrickYwriTer
1

Explanation:

tetraammidedichlorido cobalt(III)

Additional information :-

In inorganic chemistry IUPAC name is written by following steps :-

For Cationic complex :-

  • Ligan number + Ligan name + metal name (in English) + O.N. (oxidation number)

For Anionic complex :-

  • Ligan number + Ligan Name + metal name(Latin) + -ate + O.N.

For Neutral complex :-

  • Ligan number + Ligan name + metal name (in English) + O.N. (same as cationic complex)
  • Sum of oxidation number of all the atoms of a molecule is zero.
  • O.N. is written in Roman number.

Here, Ligan number is 2 and 4

Ligan name is Chlorido (Cl) and ammide (NH3).

Metal name is Cobalt.

O.N. is 3 (III).

Calculation of O.N. :-

→ x - 1 × 2 + 0 × 4 = 1

→ x = 1 + 2

→ x = 3

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