Math, asked by saumilnigam19, 1 month ago

coeff x2
(xii) (x2 - x + 1)2 + (x2 + x + 1)2

Answers

Answered by memontahla

0

Answer:

4x + 5

Step-by-step explanation:

(x2 - x + 1) 2 +(x2+x+1)2

(x2 - x + 1) 2 +(3x+1)2

(x2 - x + 1) 3x +4

(x2 - x + 1 + 3x + 4)

4x+5

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