Question

coefficient of mutual inductance of two coils is 1H. current in one of the coils is increased ftom 4-5in 1ms. what is the average emf​

Answer 1

Answer:

1000 is the correct answers

Explanation:

emf = L di/dt

hope the answer will help you

Answer 2

The average emf of given circuit is equal to 1000 V

Step by step explanation:

Coefficient of mutual inductance of two coils =  1 Henry                (given)

Current in one coil changes from 4 ampere to 5 ampere

So, Δ I = 1 ampere                                                           (given  (equation 1))

Change in time Δt = 1 ms = 0.001 second                      (given  (equation 2))

$\textbf{\large Formula of average emf = E =}\frac{L\times \delta I}{\delta t}$                   (equation (3))

Putting  The values of L,   Δ I ,  Δt in equation (3);

E = $\frac{1 \times 1}{0.001}$

$\textbf{\Large So the average emf = 1000 V}$