Question

coelliciants
Solve the pair of linear equations 5x+4y=-1 and 2x-3y 18 by the elimination method​

Answer 1

Answer:

I don't know I am sorry ok

Answer 2

Answer:  x= 3, y= -4

Explanation:

Given pair of linear equations:

5x+4y= -1  ---------------------------  (1)

2x-3y= 18 ---------------------------- (2)

To find: The value of x and y by elimination method.

Proof:

Multiplying equation (1) by 3 and equation (2) by 4, we get:

= 3( 5x + 4y = -1)

= 15 x + 12y = -3 ------------------- (3)

&

= 4 ( 2x -3y =18)

= 8x - 12y = 72 ---------------------(4)

Adding (3) and (4) we get:

= 15x+ 8x + 12y- 12y = 72 -3

⇒ 23x = 69

⇒ x = $\frac{69}{23}$

⇒ x = 3

Substituting the value of x in (1), we get:

= 5x+4y= -1

⇒ 5 (3) + 4y = -1

⇒ 15 +4y = -1

⇒ 4y = -1 -15

⇒ 4y = -16

⇒ y = $\frac{-16}{4}$

⇒ y = -4

Hence, proved.

Hope you got that.

Thank You.